Answer:
Consistent and dependent
Step-by-step explanation:
Given
[tex]3y = 9x - 6[/tex]
[tex]2y + 6x = 4[/tex]
Required
The words that describe the equations
Make y the subject in (2)
[tex]2y + 6x = 4[/tex]
Collect like terms
[tex]2y = 4 - 6x[/tex]
Divide through by 2
[tex]y = 2 - 3x[/tex]
Substitute: [tex]y = 2 - 3x[/tex] in (1)
[tex]3y = 9x - 6[/tex]
[tex]3(2 - 3x) = 9x - 6[/tex]
[tex]6 - 9x = 9x - 6[/tex]
Collect like terms
[tex]9x+9x = 6+6[/tex]
[tex]18x = 12[/tex]
Solve for x
[tex]x = \frac{12}{18}[/tex]
Simplify
[tex]x = \frac{2}{3}[/tex]
Substitute [tex]x = \frac{2}{3}[/tex] in [tex]y = 2 - 3x[/tex]
[tex]y = 2 - 3*\frac{2}{3}[/tex]
[tex]y = 2 - 2[/tex]
[tex]y =0[/tex]
So, we have:
[tex]x = \frac{2}{3}[/tex] and [tex]y =0[/tex]
The system is consistent because it has at least 1 solution
The system is dependent because it has more than 1 solution
