Answer:
(A) There should have been 5 outcomes of HT
(B) The experimental probability is greater than the theoretical probability of HT.
Step-by-step explanation:
Given
[tex]S = \{HH,HT,TH,TT\}[/tex] -- Sample Space
[tex]n(S) = 4[/tex] --- Sample Size
Solving (a); theoretical outcome of HT in 20 tosses
First, calculate the theoretical probability of HT
[tex]P(HT) = \frac{n(HT)}{n(S)}[/tex]
[tex]P(HT) = \frac{1}{4}[/tex]
Multiply this by the number of tosses
[tex]P(HT) * n= \frac{1}{4} * 20[/tex]
[tex]P(HT) * n= 5[/tex]
Solving (b); experimental probability of HT
Here, we make use of the table
[tex]P(HT) = \frac{n(HT)}{n(S)}[/tex]
[tex]P(HT) = \frac{6}{20}[/tex]
[tex]P(HT) = 0.30[/tex] ---- Experimental Probability
In (a), the theoretical probability is:
[tex]P(HT) = \frac{1}{4}[/tex]
[tex]P(HT) = 0.25[/tex] ---- Experimental Probability
By comparison;
[tex]0.30 > 0.25[/tex]
