Answer:
She will have kinetic energy at the bottom of the hill=45700 J
Explanation:
We are given that
Mass, m=60 kg
Speed, v=10 m/s
Height, h=150 m
Length of slope, d=650 m
Frictional force, f=70 N
We have to find the kinetic energy she will have at the bottom of the hill.
Kinetic energy at the bottom of the hill
=Initial kinetic energy+ mgh-fd
Substitute the values
Kinetic energy at the bottom of the hill
=[tex]\frac{1}{2}(60)(10)^2+60\times 9.8\times 150-70\times 650[/tex]
=[tex]45700J[/tex]
Hence, she will have kinetic energy at the bottom of the hill=45700 J
