Answer: The new volume of the air in the syringe is 7.3 mL.
Explanation:
Given: [tex]V_{1}[/tex] = 2.0 mL, [tex]P_{1}[/tex] = 1.02 atm, [tex]T_{1} = 22^{o}C[/tex]
[tex]V_{2}[/tex] = ?, [tex]P_{2}[/tex] = 1.27 atm, [tex]T_{2} = 100^{o}C[/tex]
Formula used to calculate the new volume in syringe is as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1.02 atm \times 2.0 mL}{22^{o}C} = \frac{1.27 atm \times V_{1}}{100^{o}C}\\V_{1} = 7.3 mL[/tex]
Thus, we can conclude that the new volume of the air in the syringe is 7.3 mL.
