Answer:
The value of the mutual force between them is 3.6 x 10⁶ N
Step-by-step explanation:
Given;
distance between the two-point charges, r = 2000 m
the value of the two-point charges, q₁ and q₂ = 40 C and -40 C
Coulomb's constant, k = 9 x 10⁹ Nm²/C²
The value of the mutual force between them is calculated by applying Coulomb's law;
[tex]F = \frac{K|q_1|q_2|}{r^2} \\\\F = \frac{(9 \times 10^9)(40\times 40)}{(2000)^2} \\\\F = 3.6 \times 10^6 \ N[/tex]
Therefore, the value of the mutual force between them is 3.6 x 10⁶ N.
