Answer:
43740 N and attractive force
Explanation:
Given that,
Charge 1, q₁ = -54.0 μC
Charge 2, q₂ = +36.0 μC
The distance between charges, r = 2 cm = 0.02 m
We need to find the force between charges. The formula for the force between charges is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
Put all the values,
[tex]F=9\times 10^9\times \dfrac{54\times 10^{-6}\times 36\times 10^{-6}}{(0.02)^2}\\\\F=43740\ N[/tex]
As the charges are opposite, the force between them is attractive. Hence, the required force is 43740 N.
