Answer:
The correct answer is "[tex]a+b+c=15[/tex]".
Step-by-step explanation:
The figure according to the given question is attached below.
Given that,
Number of people,
p = 4
Let the suitable notations are:
a, b, c, x, y, z and p
where,
Only leader M = x
Only champion M = y
Only range M = z
Exactly two medals = a+b+c
All three medals = p
The equations will be:
[tex]x+a+b+p=19[/tex]...(1)
[tex]y+a+c+p=27[/tex]...(2)
[tex]z+b+c+p=25[/tex]...(3)
[tex]x+y+z+a+b+c+p=48[/tex]...(4)
Now,
From equation (1), (2) and (3), we get
[tex]x+y+z+2(a+b+c)+3p=71[/tex]
[tex]x+y+z+2(a+b+c)=71-12[/tex]
[tex]x+y+z+2(a+b+c)=59[/tex]...(5)
By applying subtraction between equation (5) and (4), we get
[tex]a+b+c-p=59-48[/tex]
[tex]a+b+c=4+11[/tex]
[tex]a+b+c=15[/tex]