Respuesta :
Answer: There will be 41382 J energy must be absorbed by 45.0g of water to increase its temperature from [tex]83.0^{o}C[/tex] to [tex]303.0^{o}C[/tex].
Explanation:
Given: Mass = 45.0 g
Initial temperature = [tex]83.0^{o}C[/tex]
Final temperature = [tex]303.0^{o}C[/tex]
Formula used to calculate heat energy is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat energy
m = mass of substance
C = specific heat = [tex]4.18 J/g^{o}C[/tex] (here, for water)
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\= 45.0 g \times 4.18 J/g^{o}C \times (303.0 - 83.0)^{o}C\\= 41382 J[/tex]
Thus, we can conclude that there will be 41382 J energy must be absorbed by 45.0g of water to increase its temperature from [tex]83.0^{o}C[/tex] to [tex]303.0^{o}C[/tex].
