Given:
The value is [tex]\sqrt{90}[/tex].
To find:
The two consecutive whole numbers such that [tex]\sqrt{90}[/tex] lies between those numbers.
Solution:
The perfect square numbers between 1 to 100 are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100.
We know that, 90 lies between 81 and 100.
[tex]81<90<100[/tex]
[tex]9^2<90<10^2[/tex]
The value of x radical cannot be negative. So taking square root on each side, we get
[tex]\sqrt{9^2}<\sqrt{90}<\sqrt{10^2}[/tex]
[tex]9<\sqrt{90}<10}[/tex]
The given number lies between 9 and 10. Therefore, the correct option is (d)
