Answer:
The distance will be "0.319 m".
Explanation:
The diagram of the given question is not attached with the problem. Below is the attached figure.
The given values are:
[tex]q1 = -3.33\times 10^{-9} \C[/tex]
[tex]q2 = -5.22\times 10^{-9} \ C[/tex]
As we know,
The electric field will be equivalent as well as opposite throughout the direction, then
⇒ [tex]\frac{R.q1}{(0.255)^2} =\frac{R.q2}{r^2}[/tex]
⇒ [tex]r^2=\frac{q2}{q1}\times (0.255)^2[/tex]
By putting the values, we get
⇒ [tex]=\frac{-5.22\times 10^{-9}}{-3.33\times 10^{-9}}\times (0.255)^2[/tex]
⇒ [tex]=1.568\times 0.065[/tex]
⇒ [tex]r^2=0.10193[/tex]
⇒ [tex]r=\sqrt{0.10193}[/tex]
⇒ [tex]0.319 \ m[/tex]
