Answer:
Question 25:
[tex]6[/tex]
Question 19:
[tex]16[/tex]
Step-by-step explanation:
Question 25:
[tex] \frac{x}{12} + \frac{y}{3} = 2[/tex]
[tex] \frac{y}{3 } = 2 - \frac{x}{12} [/tex]
[tex]y = 3( 2 - \frac{x}{12} )[/tex]
[tex]y = 6 - \frac{x}{4} [/tex]
[tex]y = - \frac{x}{4} + 6[/tex]
Question 19:
[tex] {x}^{2} - 8x + c[/tex]
[tex] {x}^{2} + c - 18[/tex]
To find the c value ,
[tex]c = ( \frac{b}{2} {)}^{2} [/tex]
divide the coefficient of x by 2 and square the result.
[tex]( - 1 \times 4 {)}^{2} [/tex]
[tex]( - 4 {)}^{2} [/tex]
[tex]16[/tex]
Hope it is helpful....
