Answer: Heat energy contained by water is 130.625 J.
Explanation:
Given: Mass = 1.25 g
Specific heat = [tex]4.18 J/g^{o}C[/tex]
Initial temperature = [tex]20.0^{o}C[/tex]
Final temperature = [tex]45.0^{o}C[/tex]
Formula used to calculate heat energy is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat energy
m = mass of substance
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\= 1.25 g \times 4.18 J/g^{o}C \times (45.0 - 20.0)^{o}C\\= 130.625 J[/tex]
Thus, we can conclude that heat energy contained by water is 130.625 J.
