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Answer:

16.8dm3

Explanation:

2 moles of CO gives 1 mole of N2

2 moles of CO= 2* 28= 56g

1 mole of N2 = 1* 22.4dm

56g of CO gives 22.4dm3 of N2

42.7 of CO will give> (42.7*22.4)/56

=16.8dm3

The volume of [tex]N_{2}[/tex] gas will be produced 16.8 [tex]dm^{3}[/tex].

What  is volume

Volume is sometimes referred to as capacity. The volume of a cylindrical jar, for example, is used to determine how much water it can hold.

Calculation of volume is shown below:

The given reaction is: 2CO(g) + 2NO) → N2(g) + 2CO2(g)

It can be seen that 2 moles of CO give 1 mole of [tex]N_{2}[/tex].

So, 2 moles of CO = 2×28 = 56 g.

Hence, 1 mole of [tex]N_{2}[/tex] = 1×22.4 = 22.4 [tex]dm^{3}[/tex].

56 g of CO will give 22.4 [tex]dm^{3}[/tex] of nitrogen atom.

42.7 of CO will give = (42.7×22.4) / 56

= 16.8 [tex]dm^{3}[/tex].

Therefore, the volume of nitrogen will be 16.8 [tex]dm^{3}[/tex].

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