hypilot
contestada

What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total volume of 2.40 liters?

O0.104 M NaOH
O0.201 M NaOH
O0.361 M NaOH
O0.412 M NaOH

Respuesta :

Solution :

Molecular mass of NaOH is 23 g/mol .

So, number of moles of NaOH is given by :

[tex]n = \dfrac{10}{40}\ mole[/tex]

Now, we know molarity is given by :

[tex]Molarity = \dfrac{Number \ of \ moles\ of \ salute}{Volume ( in \ Liter ) }[/tex]

[tex]M = \dfrac{10}{40\times 2.4} \ M\\\\M = 0.104 \ M[/tex]

Hence, this is the required solution.