Answer:
A) 3.115 mol
B) 11.60 g h2
Explanation:
From the equation
2 mol Li gives 1 mol H2
Then 6.23 gives??
6.23 /2 = 3.116 mol H2
B) moles of Li =mass! molar mass
= 80.57/ 6.941 = 11.6 mol Li
Then moles of H2 = 11.6 /2 = 5.8 mol H2
Mass of H2 = mol * molar mass
5.8*2 =11.6 g h2
The moles of hydrogen formed with 6.23 moles of Li have been 3.115 moles. The mass of hydrogen formed with 80.57 grams of Li has been 11.60 grams.
From the balanced chemical equation,
2 moles Li = 1 mole Hydrogen
(a) The given moles of Li = 6.23 mol .
6.23 mol of Li = [tex]\rm \dfrac{1}{2}\;\times\;6.23[/tex] moles of hydrogen
6.23 mol Li = 3.115 moles of hydrogen.
The moles of hydrogen formed with 6.23 moles of Li have been 3.115 moles.
(b) The moles can be expressed as:
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles of Li in 80.57 grams:
Moles of Li = [tex]\rm \dfrac{80.57}{6.941}[/tex]
Moles of Li = 11.60 moles
The amount of Hydrogen formed:
2 moles Li = 1 mole Hydrogen
11.60 mol of Li = [tex]\rm \dfrac{1}{2}\;\times\;11.60[/tex] moles of hydrogen
11.60 mol Li = 5.803 moles of hydrogen.
Mass = moles × molecular mass
Mass of 5.803 moles of Hydrogen = 5.803 × 2
Mass of hydrogen = 11.60 grams
The mass of hydrogen formed with 80.57 grams of Li has been 11.60 grams.
For more information about the moles formed, refer to the link:
https://brainly.com/question/19085755
