Answer:
A. [tex]1.88\times 10^{-11}\,F[/tex].
Explanation:
By definition of Electric Capacitance, the capacitance of the system ([tex]C[/tex]), in farads, is described by the following formula:
[tex]C = \frac{q}{V}[/tex] (1)
Where:
[tex]q[/tex] - Electric charge, in coulombs.
[tex]V[/tex] - Voltage, in volts.
If we know that [tex]q = 9.4\times 10^{-10}\,C[/tex] and [tex]V = 50\,V[/tex], then the capacitance of the system is:
[tex]C = \frac{9.4\times 10^{-10}\,C}{50\,V}[/tex]
[tex]C = 1.88\times 10^{-11}\,F[/tex]
The correct answer is A.
