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How much work (in J) is involved in a chemical reaction if the volume decreases from 5.20 to 1.13 L against a constant pressure of 0.852 atm ? Express your answer to three significant figures and include the appropriate units.

Respuesta :

Answer:

W = 350.6 J

Explanation:

Given that,

The volume decreases from 5.20 to 1.13 L against a constant pressure of 0.852 atm.

The change in volume = 1.13 L - 5.20 L = -4.07 L

Work done, W = - PΔV

So,

W = 0.852 atm × -4.07 L

= - 3.46 L-atm

or

[tex]W=3.46\ L-atm\times \dfrac{101.33\ J}{1\ L-atm}\\\\=350.6\ J[/tex]

So, the required work done is 350.6 J.

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