graph the line with intercept 6 and slope
[tex] - \frac{3}{2} [/tex]

Given:
The y-intercept of a line = 6
The slope of the line = [tex]-\dfrac{3}{2}[/tex]
To find:
The graph of the given line.
Solution:
The slope intercept form of a line is:
[tex]y=mx+b[/tex]
Where, m is the slope and b is the y-intercept.
Putting [tex]m=-\dfrac{3}{2}[/tex] and [tex]b=6[/tex] in the above equation, we get
[tex]y=-\dfrac{3}{2}x+6[/tex]
At [tex]x=0[/tex],
[tex]y=-\dfrac{3}{2}(0)+6[/tex]
[tex]y=0+6[/tex]
[tex]y=6[/tex]
At [tex]x=2[/tex],
[tex]y=-\dfrac{3}{2}(2)+6[/tex]
[tex]y=-3+6[/tex]
[tex]y=3[/tex]
Plot these two points (0,6) and (2,3) on a coordinate plane and connect them by a straight line to get the graph of the required line.
The required graph is shown below.