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Find the 40th term of the arithmetic sequence with a = 150 and a common difference of d =-4.
1.-6
2.6
3.-2
4.2

Respuesta :

reinhard10158

Answer:

1. -6

Step-by-step explanation:

a1 = 150

a2 = a1 - 4 = 150 - 4 = 146

a3 = a2 - 4 = a1 - 4 - 4 = 146 - 4 = 150 - 4 - 4 = 142

...

=>

an = a1 - (n-1)×4

=>

a40 = a1 - 39×4 = 150 - 156 = -6

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