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8f(x)=x

2

+6x+8f, left parenthesis, x, right parenthesis, equals, x, squared, plus, 6, x, plus, 8

1) What are the zeros of the function?

Write the smaller xxx first, and the larger xxx second.

\text{smaller }x=smaller x=start text, s, m, a, l, l, e, r, space, end text, x, equals

\text{larger }x=larger x=start text, l, a, r, g, e, r, space, end text, x, equals

2) What is the vertex of the parabola?

Respuesta :

abidemiokin

Answer:

-2 and -4

Step-by-step explanation:

Given the function f(x) = x² + 6x + 8

If f(x) = 0

x² + 6x + 8 = 0

Factorize

x² + 4x + 2x+ 8 = 0

x(x+4)+2(x+4) = 0

(x+2)(x+4) = 0

x+2 = 0 and x+4 = 0

x = -2 and -4

Hence the zero of the function is -2 and -4

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