Answer:
c. 0.6
Step-by-step explanation:
A student cannot receive an A or a B simultaneously, so [tex]P(A \cap B) = 0[/tex].
Grade of A equals .30 and the probability of receiving a grade of B equals .30.
This means that [tex]P(A) = P(B) = 0.3[/tex]
The probability that a randomly selected student from this class will receive either an A or a B equals:
This is:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.3 + 0.3 - 0 = 0.6[/tex]
So the probability is 0.6, and the correct answer is given by option c.
