Type the correct answer in the box. Use numerals instead of words. What value of x satisfies this equation? log2 (6x – 8) – log2 8 = 1 The value of x is​

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You can use two important properties of log to find out the solution of the given equation.

The value of x that satisfies the given equation is 4

What is logarithm and some of its useful properties?

When you raise a number with an exponent, there comes a result.

Lets say you get

[tex]a^b = c[/tex]

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

[tex]b= log_a(c)[/tex] ,  here 'a' is called base of logarithm.

Some properties of logarithm are:

[tex]log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(a) = 1[/tex]  

(take special attention over that base "a" in all of the above property as you might mix them with other base logarithms which is not allowed)

How to find the solution to the given equation?

We can use the fourth, property and then can use third and first property as follows:

[tex]log_2(6x-8) - log_2(8) = 1\\\\log_2(\frac{6x-8}{8}) = log_2(2)\\\\\dfrac{6x-8}{8} = 2\\\\6x-8 = 2 \times 8\\6x-8 = 16\\6x = 16 + 8\\6x = 24\\\\x = \dfrac{24}{6} = 4\\\\x= 4[/tex]

Thus, the value of x for the given condition is obtained as 4.

Learn more about logarithms here:

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