Answer:
The width of the pathway is 5.2 feet
Step-by-step explanation:
Given that the shape of the garden and the walkway is a rectangle, the walkway would have the same length as the garden but would have it's own width.
Let the width of the garden be W and that of the walkway be t while the length of both the garden and walkway is L. The combined area A
= L( W + t)
Given that the combined area of the garden and the border 311 square feet while the garden is 14 feet by 17 feet
311 = 14 (17 + t)
311 = 238 + 14t
collect like terms
14t = 311 - 238
14t = 73
t = 73/14
= 5.2 feet
