The demand for personal computers has been estimated to be Q = 500,000 – 700P +200I - 500S. Assume that per capita income I is $13,000 and the average price ofsoftware S is $400.When the price of personal computers is P = $3,000, the priceelasticity of demand is:________.a. –2.625b. –7.0c. –1.0d. –21.0e. –4.25

Respuesta :

Answer:

The price elasticity of demand is: -2.625

Explanation:

Given

[tex]Q = 500000 - 700P +200I - 500S[/tex] --- the demand

[tex]I =\$13000[/tex] --- per capita income

[tex]S = \$400[/tex] --- average price of software

[tex]P = \$3000[/tex] --- price of computer

Required

The price elasticity of demand

Substitute values for I and S in: [tex]Q = 500000 - 700P +200I - 500S[/tex]

[tex]Q = 500000 - 700P +200*13000 - 500*400[/tex]

Collect like terms

[tex]Q = 500000 +200*13000 - 500*400- 700P[/tex]

[tex]Q = 2900000- 700P[/tex]

The price elasticity (n) is then calculated using:

[tex]n =\frac{P}{Q} * \frac{dQ}{dP}[/tex]

[tex]Q = 2900000- 700P[/tex]

Differentiate

[tex]\frac{dQ}{dP} = -700[/tex]

Calculate Q when [tex]P = \$3000[/tex]

[tex]Q = 2900000- 700*3000[/tex]

[tex]Q = 800000[/tex]

So, we have:

[tex]n =\frac{3000}{800000} * -700[/tex]

[tex]n =-\frac{3000* 700}{800000}[/tex]

[tex]n =-\frac{2100000}{800000}[/tex]

[tex]n =-\frac{21}{8}[/tex]

[tex]n =-2.625[/tex]

The price elasticity of demand is going to be –2.625.

The equation has

Q = 500,000 – 700P +200I - 500S.

p =  $3,000

I = $13,000

S = $400

We have to put in these values in the equation that we have here:

Q =  500,000 – 700*3000 +200*13000 - 500*400

= 800000

We have to find dQ/dP

=  500,000+200*13000 - 500*400 – 700P

= 2900000-700p

= -700p

The price elasticity =

-700*3000/800000

= -2.625

The price elasticity =   -2.625

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