Respuesta :
Answer:
High concentration
Higher charge on the ions
Explanation:
Ideally, the Van't Hoff factor is defined as the ratio between the actual concentration of particles produced when the substance is dissolved in a solution and the concentration of a substance as calculated from its mass(Wikipedia).
The Van't Hoff factor is influenced by the concentration of ions in solution as well as the magnitude of charge on the ions in solution.
Highly charged ions tend to remain paired in solution thereby leading to a lower value of Van't Hoff factor. Also, in highly concentrated solutions, the Van't Hoff factor is lower than in dilute solutions due to the pairing of ions
The conditions that would increase the effect of ion-pairing and decrease the observed van 't Hoff factor are a high concentration of solute and a higher charge on the ions.
Explanation:
- A number of particles are formed by dissolving a unit molecule of a solute in a solvent.
- The higher concentration of solution lowers the value of the van 't Hoff factor as ionic compounds do not get completely dissociated in their aqueous solution.
- Also, some ions form ion pairs (pairing of opposite charges in the aqueous state) and exist as a single particle which decreases the value of the van 't Hoff factor.
- The ions with higher charges have a greater tendency to form ion-pair due to their high electrostatic interaction.
So, from this, we can conclude that conditions that would increase the effect of ion-pairing and decrease the observed van 't Hoff factor are a high concentration of solute and a higher charge on the ions.
Learn more about the van 't Hoff factor here:
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