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Jolene invests her savings in two bank accounts, one paying 3 percent and the other paying 9 percent simple interest per year. She puts twice as much in the lower-yielding account because it is less risky. Her annual interest is 6015 dollars. How much did she invest at each rate?

Respuesta :

Answer and Explanation:

The computation is shown below:

Let us assume X be the amount invested at 3%

And, Y be the amount invested at 9%

So,  

0.03X + 0.09Y = $6,015 ........(1)

 X = 2Y ...........(2)

Now put the value of X in equation 1  

 0.03(2Y) + 0.09Y  = $6,015

 0.06Y + 0.09Y = $6,015

 0.15Y = $6,015

Y = $40,100

 X = 2 × $40,100 = $80,200

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