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Triangle PQR has vertices P(-2, 6), Q(-8, 4) and R(1, -2). It is translated according to the rule (x, y)—> (x, - 2, y -16).
What is the y-value of P’?

a. -18

b. -16

c. -12

d. -10

Triangle PQR has vertices P2 6 Q8 4 and R1 2 It is translated according to the rule x ygt x 2 y 16 What is the yvalue of P a 18 b 16 c 12 d 10 class=

Respuesta :

Answer:  -10  (choice D)

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To find this answer, you apply the given translation rule to the coordinates of point P(-2,6)

[tex](x,y) \to (x-2, y-16)\\\\(-2,6) \to (-2-2, 6-16)\\\\(-2,6) \to (-4, -10)\\\\[/tex]

We see that point P' has a y coordinate of -10

This translation, aka shifting, rule moved point P 2 units to the left and 16 units down.

andreansalazar

Answer:last one D ( -10)

Step-by-step explanation:

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