How many distinct 5 digit numbers can be formed from the list of numbers
{0,1,2,3,4,5,6,7,8,9}such that the number
i. Is an even number
ii. Is a Odd number
iii. Multiple of 5
iv. Never ends with {2,3,4,5}
Case 1: A 5 digit number with the digits {1,2,3,4,5}. Since 0 is not a part of this set and there are 5 different digits, we can form a total of 5P5 = 5! = 120 numbers.
