Answer:
Step-by-step explanation:
If the diagonals of the rectangle are congruent,
AC = BD
By using formula to calculate the distance between two points,
Distance between two points = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Distance between A(0, -3) and C(2, 8),
AC = [tex]\sqrt{(8+3)^2+(2-0)^2}[/tex]
= [tex]\sqrt{125}[/tex]
= [tex]5\sqrt{5}[/tex]
Similarly, distance between two points B(-4, 0) and D(6, 5),
BD = [tex]\sqrt{(5-0)^2+(6+4)^2}[/tex]
= [tex]\sqrt{125}[/tex]
= [tex]5\sqrt{5}[/tex]
Therefore, both the diagonals are congruent.
Hence, given quadrilateral ABCD is a rectangle.
