Answer:
See explanation and image attached
Explanation:
The image attached shows the entire scheme of reactions mentioned in the question.
The first reaction is an addition reaction which yields a tertiary alkyl halide as shown in accordance with Markovnikov rule.
The second reaction is a dehydrohalogenation in which the base abstracts a proton from the alkyl halide followed by loss of a bromide ion to yield the corresponding alkene.
This alkene is an isomer of the starting material.
