Answer:
The predicted final exam grade is 83
Step-by-step explanation:
Given
[tex]\bar x = 75[/tex] -- midterm mean
[tex]\sigma_x = 10[/tex] --- midterm standard deviation
[tex]\mu =75[/tex] --- final mean
[tex]\sigma = 10[/tex] --- final standard deviation
[tex]r = 0.8[/tex]
Required
The predicted final grade of student who score 85 in midterm
The prediction is represented as:
[tex]y = \alpha + \beta x[/tex]
Where:
[tex]\beta = r * \frac{\sigma}{\sigma_x}[/tex]
[tex]\beta = 0.8 * \frac{10}{10}[/tex]
[tex]\beta = 0.8 * 1[/tex]
[tex]\beta = 0.8[/tex]
and
[tex]\alpha = \mu - r * \bar x[/tex]
[tex]\alpha = 75- 0.8 * 75[/tex]
[tex]\alpha = 75- 60[/tex]
[tex]\alpha = 15[/tex]
So:
[tex]y = \alpha + \beta x[/tex]
[tex]y = 15 + 0.8x[/tex]
For a student who gets 85, the prediction is:
[tex]y = 15 + 0.8*85[/tex]
[tex]y = 15 + 68[/tex]
[tex]y = 83[/tex]