What is the equation, in point-slope form, of the line that
is perpendicular to the given line and passes through the
point (-4,-3)?

What is the equation in pointslope form of the line that is perpendicular to the given line and passes through the point 43 class=

Respuesta :

Answer:

Step-by-step explanation:

We first need to find the slope of the line that is graphed. We can wither use the slope formula or you can use the slope triangle. From the upper point on the line (-1, 1) count down til you're on the same horizontal as the lower point on the line (0, -3). You have to count down 4 (which is -4) and over to the right 1 (which is +1). So -4/+1 = -4 and the slope is -4. That means that the perpendicular slope, the opposite reciprocal of that, is 1/4. Using that slope and the point (-4, -3), the point-slope form of the line is

[tex]y-(-3)=\frac{1}{4}(x-(-4))[/tex] which we can simplify a bit to

[tex]y+3=\frac{1}{4}(x+4)[/tex]. That's the line in point-slope form.