Answer:
1. 78.9g of CO
2. 104.9g Fe and 124.0g CO2
Explanation:
Based on the balanced reaction:
Fe2O3 (s) + 3CO (g) -> 2Fe(s) + 3CO2 (g)
1 mole of Fe2O3 reacts with 3 moles of CO to produce 2 moles of Fe and 3 of CO2
1. The moles of 0.150kg = 150g of Fe2O3 -Molar mass: are:
150g * (1mol / 159.69g) = 0.9393 moles Fe2O3
Moles CO:
0.9393 moles Fe2O3 * (3mol CO / 1mol Fe2O3) = 2.818 moles CO
Mass CO -Molar mass: 28.01g/mol-:
2.818 moles CO * (28.01g/mol) = 78.9g of CO
2. The moles of Fe produced are:
0.9393 moles Fe2O3 * (2mol Fe / 1mol Fe2O3) = 1.8786 moles Fe
Mass Fe -Molar mass: 55.845g/mol-:
1.8786 moles Fe * (55.845g/mol) = 104.9g Fe
The moles of CO2 produced are:
0.9393 moles Fe2O3 * (3mol CO2 / 1mol Fe2O3) = 2.818moles CO2
Mass CO2 -Molar mass: 44.01g/mol-:
2.818moles CO2 * (44.01g/mol) = 124.0g CO2
