Answer:
x = 10 + log(1/a^12)/(2 log(a)) + (i π n)/log(a) for n element Z
Step-by-step explanation:
Solve for x:
a^(20 - 2 x) = a^12
Take reciprocals of both sides:
a^(2 x - 20) = 1/a^12
Take the logarithm base a of both sides:
2 x - 20 = log(1/a^12)/log(a) + (2 i π n)/log(a) for n element Z
Add 20 to both sides:
2 x = 20 + log(1/a^12)/log(a) + (2 i π n)/log(a) for n element Z
Divide both sides by 2:
Answer: x = 10 + log(1/a^12)/(2 log(a)) + (i π n)/log(a) for n element Z
