Answer:
C. The graph of the function starts high and ends low
Step-by-step explanation:
For [tex]f(x)=-x^5+x^2-x[/tex], as [tex]x[/tex] approaches negative infinity, [tex]f(x)[/tex] approaches infinity, and as [tex]x[/tex] approaches infinity, [tex]f(x)[/tex] approaches negative infinity.
Thus, we have:
[tex]\lim_{x\rightarrow -\infty}f(x)=\infty,\\\lim_{x\rightarrow \infty}f(x)=-\infty[/tex]
This corresponds with answer choice C. The graph of the function starts high and ends low.