For the following set of data, find the percentage of data within 2
population standard deviations of the mean, to the nearest percent.
58, 77, 31, 54, 58, 54, 56, 58, 56

Respuesta :

Answer:

58,+77,+31,+54+,58+,54+,46+,58+,56/9

If the value of the mean is 55.78. Then the standard deviation will be 10.98.

What is a standard deviation?

It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.

The data set is given below.

58, 77, 31, 54, 58, 54, 56, 58, 56.

Then the mean of the data set will be

Mean = (58 + 77 + 31 + 54 + 58 + 54 + 56 + 58 + 56) / 9

Mean = 502 / 9

Mean = 55.78

Then the standard deviation will be

[tex]\rm SD = \sqrt{\dfrac{(58 - 55.78)^2+(77-55.78)^2 + ..... + (56-55.78)^2 }{9}}\\\\SD = \sqrt { \dfrac{1085.5}{9}}\\[/tex]

On further solving we have

SD = 10.98

If the value of the mean is 55.78. Then the standard deviation will be 10.98.

More about the standard deviation link is given below.

https://brainly.com/question/12402189

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