The 3 real roots of the given equation.
To find the real roots.
What is quadratic equation?
Any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power. The quadratic formula to solve a quadratic equation ax2 + bx + c = 0 is x = [-b ± √(b2 - 4ac)]/2a.
Given that:
The equation are
[tex]\sqrt{2x+4}=\frac{1}{2x} +1\\[/tex]
By squaring both sides
[tex]2x+4=\frac{1}{4x^{2} }+1+\frac{1}{x} \\\\2x-\frac{1}{x}+3=\frac{1}{4x^{2} }\\\\8x^{3}-4x+12x^{2} -1=0\\ \\8x^{3}+12x^{2}-4x -1=0[/tex]
By solving quadratic equation ,
Solutions for x
x1 = -1.74543
x2 = -0.17169
x3 = 0.41712
So, the 3 real roots of the given equation.
Learn more about quadratic equation here:
https://brainly.com/question/24116590
#SPJ2
