(a) 39 V
(b) 7.8 V
(a) Neglecting the internal resistance of the battery, the voltage drop (V) across the battery is found from Ohm's law as follows;
V = IR -------------------------(i)
Where;
I = current through the battery
R = total resistance of the circuit.
From the question;
I = 0.75A
R = 52.0Ω
Substitute the values of I and R into equation (i)
=> V = 0.75 x 52.0
=> V = 39Volts
Therefore, the voltage drop across the battery is 39 Volts
(b) Since the set of lanterns is connected in series, then the same current flows through each of the lanterns. Also, since the lanterns are identical, the resistance ([tex]R_{L}[/tex]) of each of them is given by the total resistance (R = 52.0Ω) divided by the number of lanterns. i.e
[tex]R_{L}[/tex] = [tex]\frac{52.0}{5}[/tex]
[tex]R_{L}[/tex] = 10.4Ω [Each lantern has a resistance of 10.4Ω]
The current flowing through them is the same as the current (I = 0.75A) flowing the circuit.
Therefore, using Ohm's law, the voltage drop ([tex]V_L[/tex])across each load (lantern) is
[tex]V_L[/tex] = I x [tex]R_{L}[/tex]
[tex]V_L[/tex] = 0.75 x 10.4
[tex]V_L[/tex] = 7.8Volts
Therefore, the voltage drop across each load is 7.8 Volts
