Answer:
4x²+21x-2
(OR)
2x²-x-6
Step-by-step explanation:
According to the Question,
Given, The difference Between two trinomials is x²-10x+2 & If one of the trinomials is 3x²-11x-4.
Let, Two Trinomials are P(x) = A & Q(x) = 3x²-11x-4
Then, P(x) - Q(x) = x²-10x+2
Put Value, We get
A - (3x²-11x-4) = x²-10x+2
A = x²-10x+2 + (3x²-11x-4)
A = x²-10x+2 + 3x²-11x-4
A = 4x²+21x-2
(OR)
If we Let, Two Trinomials are Q(x) = A & P(x) = 3x²-11x-4
Then, P(x) - Q(x) = x²-10x+2
Put Value, We get
(3x²-11x-4) - A = x²-10x+2
A = 3x²-11x-4 - (x²-10x+2)
A = 3x²-11x-4 - x²+10x-2
A = 2x²-x-6
