The length of the hypotenuse of the triangle whose other two sides are of the length 5√2 units is given by: Option B: 10 units.
What is Pythagoras Theorem?
If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:
[tex]|AC|^2 = |AB|^2 + |BC|^2[/tex]
where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).
For this case, consider the figure attached below.
Then, we are given the facts that:
- Triangle ABC is a right angled triangle with right angle at vertex B
- The lengths of non-hypotenuse sides AB and BC are 5√2 units
- The length of the hypotenuse AC, denoted by h is to be found.
Using the Pythagoras theorem, we get:
[tex]|AC|^2 = |AB|^2 + |BC|^2\\\\h^2 = (5\sqrt{2})^2 + (5\sqrt{2})^2 \\\\h^2 = 2(5\sqrt{2}))^2[/tex]
Taking root, we get:
[tex]h = \sqrt{2 (5\sqrt{2})^2}[/tex] (only positive root since h is denoting length, which is a non-negative quantity).
Thus, we get:
[tex]h = \sqrt{2 (5\sqrt{2})^2} = \sqrt{(5\sqrt{2})^2} \times \sqrt{2} = (5\sqrt{2}) \times \sqrt{2} = 5 \times (\sqrt{2})^2 = 5 \times 2 \\\\h= 10 \: \rm units[/tex]
(square cancelled the square root).
Thus, the length of the hypotenuse of the triangle whose other two sides are of the length 5√2 units is given by: Option B: 10 units.
Learn more about Pythagoras theorem here:
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