Answer:
[tex]AB[/tex] is parallel to [tex]CD[/tex] ([tex]AB ||CD[/tex])
Step-by-step explanation:
In a set of parallel lines cut by the traversal, [tex]\angle AHG[/tex] and [tex]\angle DGH[/tex] are alternate interior angles. In a set of parallel lines cut by a traversal, alternate interior angles are always equal. Therefore, since [tex]\angle AHG=\angle DGH=115^{\circ}[/tex] (they are equal), the lines AB and CD must be parallel.
*A set of parallel lines proves that alternate interior angles are always equal, but the converse is also true in that equal alternate interior angles proves a set of parallel lines. This is because if you changed the angle measure of either of the angles, the relative slope of the lines must change and they would no longer be parallel.
