Answer:
The correct solution is "0.66104".
Explanation:
Given:
Component 1,
[tex]\beta=1.3[/tex]
[tex]\gamma=24,000 \ hr[/tex]
Component 2,
[tex]\beta = 1.9[/tex]
[tex]\gamma=18,000 \ hr[/tex]
Component 3,
[tex]MTTF=48,000 \ hr[/tex]
Now,
At t = 6000 hr, the system reliability will be:
⇒ [tex]Rs(t=6000)=\frac{3}{\pi} R_1\times R_2\times R_3[/tex]
[tex]=[e^{-(\frac{6000}{24000} )^{1.3}}]\times [e^{-(\frac{6000}{18000} )^{1.9}}]\times [e^{-(\frac{6000}{48000} )}][/tex]
[tex]=0.66104[/tex]
Thus the above is the correct solution.