Answer:
Hence the true proportion is (0.388, 0.492).
Step-by-step explanation:
Given n=250,
[tex]p= 110/250 =0.44[/tex]
[tex]a=0.1, |Z(0.05)|=1.645[/tex] (check standard normal table)
So 90% CI is
[tex]p ± Z*√[p*(1-p)/n]\\0.44 ± 1.645*sqrt(0.44*(1-0.44)/250)\\ ( 0.388, 0.492)[/tex]