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A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft lanes with a 4-ft shoulder on the right side and 2-ft shoulder on the left. The peak-hour factor is 0.84 and the traffic stream has a heavy vehicle adjustment factor of 0.847. If the analysis flow rate is 1250 pc/h/ln, what is the peak-hour volume

Respuesta :

Answer:

1779 veh/h

Explanation:

Given :

Peak hour factor, PHF = 0.84

Heavy vehicle adjustment factor, [tex]$F_{HV}$[/tex] = 0.847

Analysis flow rate, [tex]v_p[/tex] = 1250 pc/h/ln

We know that,

Analysis flow rate, [tex]$v_p=\frac{v}{(PHF)(N)(F_g)(F_{HV})}$[/tex]

Here, v = peak hour volume

         [tex]$F_g$[/tex] = grade adjustment factor which is 0.99 for rolling terrain.

               > 1200 pc/h/ln

[tex]$v_p=\frac{v}{(PHF)(N)(F_g)(F_{HV})}$[/tex]

[tex]$1250=\frac{v}{(0.84)(2)(1)(0.847)}$[/tex]

v = 1779 veh/h

Therefore, the peak hour volume, v = 1779  veh/h

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