Answer: Molarity of the unknown calcium hydroxide solution is 0.217 M.
Explanation:
Given: [tex]V_{1}[/tex] = 50.00 mL, [tex]M_{1}[/tex] = ?
[tex]V_{2}[/tex] = 43.43 mL, [tex]M_{2}[/tex] = 0.250 M
Formula used is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\M_{1} \times 50.00 mL = 0.250 M \times 43.43 mL\\M_{1} = \frac{0.250 M \times 43.43 mL}{50.00 mL}\\= 0.217 M[/tex]
Thus, we can conclude that molarity of the unknown calcium hydroxide solution is 0.217 M.
