Respuesta :
Answer: The chemical formula is [tex]XSO_3[/tex]
Explanation:
Ionization energy is defined as the amount of energy that is required to remove an electron from a chemical species.
The ionization energy equation for the given values follow:
[tex]X(g)\rightarrow X^+(g)+e^-;E_I=590kJ/mol[/tex]
[tex]X^+(g)\rightarrow X^{2+}(g)+e^-;E_I=1145kJ/mol[/tex]
[tex]X^{2+}(g)\rightarrow X^{3+}(g)+e^-;E_I=4912kJ/mol[/tex]
From the values of ionization energy above, it can be seen that the ionization energy increases as every succeeding electron is removed.
Second ionization energy is a little higher than the first one but there is a huge amount of difference between the third and second ionization energy.
This implies that the ion formed during second ionization energy has a stable configuration and it requires a humongous amount of heat to release the third electron.
Hence, the ion formed will be [tex]X^{2+}[/tex]
Sulfite ion is a polyatomic ion having a chemical formula of [tex]SO_3^{2-}[/tex]
An ionic compound is formed between the two ions and the chemical compound formed between the two will have a formula of [tex]XSO_3[/tex]
Hence, the chemical formula is [tex]XSO_3[/tex]
The likely formula of a compound formed between X and the sulfite ion is XSO3.
The ionization energy of an atom refers to the energy required to remove an electron from the atom. There are as many possible ionization energies in an atom as there are electrons in the atom.
However, If we go past the valence shell of an atom, we will experience a jump in the ionization energy. This jump is an usually high increase in ionization energy due to the removal of an electron from an inner shell.
As we can see from the values of ionization energy presented in the question, A jump occurs after the second ionization energy implying that the atom has two valence electrons. The third electron is removed from an inner shell.
From all that has been said above, a likely formula of a compound formed between the element X and the sulfite ion is XSO3.
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