contestada

The number of radioactive nuclides from a radioactive source has reduced to 1/6
from its original value in 60 seconds. Find the decay constant for this source.​

Respuesta :

Answer:

λ = 0.03 s⁻¹

Explanation:

The formula for decay constant can be used as follows:

[tex]N = N_oe^{-\lambda t}\\\\\frac{N}{N_o} = e^{-\lambda t}[/tex]

where,

[tex]\frac{N}{N_o}[/tex] = ratio of remaining nuclei to the initial value of nuclei = [tex]\frac{1}{6}[/tex] = 0.167

t = time = 60 s

λ = decay constant = ?

Therefore,

[tex]0.167 = e^{-\lambda(60\ s)}\\\\-\lambda (60\ s) = ln(0.167)\\\\\lambda = \frac{-1.7917}{- 60\ s}[/tex]

λ = 0.03 s⁻¹