Answer:
YES
Step-by-step explanation:
Find each length using the distance formula, [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
✔️Distance between A(-4, 2) and B(1, 4):
[tex] AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Let,
[tex] A(-4, 2) = (x_1, y_1) [/tex]
[tex] B(1, 4) = (x_2, y_2) [/tex]
[tex] AB = \sqrt{(1 - (-4))^2 + (4 - 2)^2} [/tex]
[tex] AB = \sqrt{(5)^2 + (2)^2} [/tex]
[tex] AB = \sqrt{25 + 4} [/tex]
[tex] AB = \sqrt{29} [/tex]
✔️Distance between C(2, -1) and D(4, 4):
[tex] CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Let,
[tex] C(2, -1) = (x_1, y_1) [/tex]
[tex] D(4, 4) = (x_2, y_2) [/tex]
[tex] CD = \sqrt{(4 - 2)^2 + (4 - (-1))^2} [/tex]
[tex] CD = \sqrt{(2)^2 + (5)^2} [/tex]
[tex] CD = \sqrt{4 + 25} [/tex]
[tex] CD = \sqrt{29} [/tex]
AB = CD = √29
Therefore, they both have the same length.
