Step-by-step explanation:
we solve for x
15x-(2/x)>1. /*x
15x^2 -2 > x. /-x
15x^2 -x -2 > 0
Solve the quadratic at zero
15x^2 -x -2=0
using the quadratic formula
x1,2 = [1+-sprt((-1)^2-4(15)(-2))]/2(15)
= [1+- sqrt (121)]/30
= [1+-11]/30
x1= 12/30= 2/5
x2= -10/30= -1/3
therefore this positive parabola is greater than zero or positive when
x< -1/3 and x> 2/5
