What is the solution set to this equation?
log_4(x + 3) + log_4x = 1

Answer:
x=1
Step-by-step explanation:
log_4(x + 3) + log_4x = 1
We know that loga(b) + loga(c) = loga(bc)
log_4(x + 3)x = 1
Raise each side to the base of 4
4^log_4(x + 3)x = 4^1
(x+3)x = 4
x^2 +3x = 4
Subtract 4 from each side
x^2 +3x -4 = 0
Factor
(x+4) (x-1) =0
Using the zero product property
x= -4 x=1
But x cannot be negative since logs cannot be negative
x=1
Answer:
A.. x = 1.
Step-by-step explanation:
log_4(x + 3) + log_4x = 1
log_4 x(x + 3) = log_4 4
Removing the logs:
x(x + 3) = 4
x^2 + 3x - 4 = 0
(x + 4)(x - 1) = 0
x = 1, -4.
We can ignore the -4 as there is no log of a negative.